SE Telegram

After you become familiar with the basic rules and procedures of Square Edging, you can use the SE Telegram, to ease up the computation. It is a combination of doing some parts mentally and writing some other parts directly without the formal representations, such as the use of square sign, equal sign and omitting some letters and others, not so important.

Example:

√38,775,529

Step 1: Determine first, the two IPS (initial possible square roots). There is no need to write down the middle letters M and N

*At Left Column, 1^st Row

√38,775,529

... 6 ......... 3

... 6 ......... 7

Step 2: Create a modified P CHK.

1) On the first line, write down the notation “ P: ” followed by the first 4 digits of the given problem.

2) On the second line, write down the middle numbers, separated by a colon “ : ” and no square sign. On its right side, draw an arrow, either an up ↑ or down ↓ arrow, based on the following conditions:

Condition 1: If P is less than the middle square value, draw a down ↓ arrow

Condition 2: If P is greater than the middle square value, draw an up ↑ arrow

3)On the third line, write down M, followed by an either a 5↑ or a 4↓, based on the following conditions:

Condition 4: If the arrow on the second line is ↑, write down 5↑, then on its right side, write the notation /_ 750/

Condition 5: If the arrow on the second line is ↓, write down 4↓, then on its right side, write the notation /_ 250/

*At Right Column, 1^st Row

.....P: 38’77

. 65 : 42’25 ↓

....M : 4↓ / 6250/

Step 3: Start computing the SE data.

Let’s begin with 6MN3

1) Looking for the ‘N’ digits

* At Left Column, 2^nd Row

N3 : 09

(Blank)

....... 2 ... ← (take note, the 2 here is the second to the last digit of the given problem)

The letter N is included because we’re looking for that missing digit. Leave the second line blank and ask your self this question:

Q: What number needed to add to 0 to have a sum of 2?

A: 2

Write down on the second line “ Nx6 ” (6 is the double value of 3), followed by a colon :, then the answer “2”. On their right, decide which “pair of multiplicands” is the correct combination:

..... N3 : 09

... Nx6 : 2 . ..... 2, 7

............. 2

2) Looking for the M digits

Since we’re doing some parts mentally, directly write down the two combinations from the digits we gathered:

* At Left Column, 3^rd Row

..... 23 : 4’09

... 2x6 : 1’2 .

............ 5’29

. Mx6 :(Blank)

............ 5 ← (this is the third to the last digit of the given problem)

Leaving some space in the second line blank, give you time to think first of what digit to write, by looking for a number needed to add to come up with the correct sum

..... 23 : 4’09

... 2x6 : 1’2 .

............ 5’29

. Mx6 : 0 . ... 0, 5

............ 5

6023

Underline the 0 since in P Chk, 4↓ indicates that the digits for M is 4 below.

Write down on the sixth line, the first complete digits of the first possible square root

Helpful Tip: Write down first 0, then 23 and then look for the first digit 6, so you would not be confused in writing down 6023

Do the Same procedures for the combination 73

* At Left Column, 4^th Row

..... 73 : 49’09

... 7x6 : 4’2 .

............ 3’29

. Mx6 : 2 . ... 2, 7

............ 5

6273

On the right column, below the P- Chk, do the same procedures starting from Step 3, to complete the data for the second IPS ( 6MN7)

*At Right Column, 2^nd Row

..... N7 : 49

... Nx4 : 8 . ..... 2, 7

............. 2

*At Right Column, 3^rd Row

....... 27 : 4’49

... 2x14 : 2’8 .

.............. 7’29

... Mx4 : 8 . ... 2, 7

.............. 5

6227

*At Right Column, 4^th Row

....... 77 : 49’49

..... 7x14 : 9’8 .

................ 9’29

..... Mx4 : 6 . ... 4, 9

................ 5

6477

Step 4: Arrange the 4 possible square roots from the lowest value to the highest by inserting the letters A, B, C, D on their right sides to avoid writing them again.

A - the lowest possible square root

B - 2^nd to the lowest

C - 2^nd to the highest

D – the highest of all

At Left Column ..... At Right Column

...... 6023 (A) .................... 6227 (B)

...... 6273 (C) ..................... 6477 (D)

Step 5: Use the Square Root locator to determine which of the 4 possible square roots will remain

42’25

(Blank)

36’00 .

78’25 / 2

39’12

Leave the second line (M) blank. Add 42’25 (H) and 36’00 (L).

We come up with a sum of 78’25. Divide by 2

Doing it mentally, always subtract the quotient by 6.

* At Left Column, 5^th Row

42’25

39’06 \ ↓ (Using this middle value as reference, the P: 38’77 is lesser than)

36’00 /

78’25 / 2

39’12

The ↓ arrow indicates that the two higher values (C and D) are eliminated. A and B remained

Step 6: Use the 2^nd Square Root Locator to determine which of the two remaining possible square roots, is the true square root of 38,775,529

39’06

(Blank)

36’00

75’06/2

37’53

Complete the data and determine where P is located

*At Right Column, 5ht Row

39’06\

37’53/ ↑

36’00

75’06/2

37’53

We therefore choose B as the true square root

√38,775,529 = 6,227