Showing posts with label SE. Show all posts
Showing posts with label SE. Show all posts

Friday, August 13, 2010

SE Telegram

After you become familiar with the basic rules and procedures of Square Edging, you can use the SE Telegram, to ease up the computation. It is a combination of doing some parts mentally and writing some other parts directly without the formal representations, such as the use of square sign, equal sign and omitting some letters and others, not so important.


Example:


√38,775,529


Step 1: Determine first, the two IPS (initial possible square roots). There is no need to write down the middle letters M and N


*At Left Column, 1st Row


√38,775,529

... 6 ......... 3

... 6 ......... 7


Step 2: Create a modified P CHK.


1) On the first line, write down the notation “ P: ” followed by the first 4 digits of the given problem.


2) On the second line, write down the middle numbers, separated by a colon “ : ” and no square sign. On its right side, draw an arrow, either an up ↑ or down ↓ arrow, based on the following conditions:


Condition 1: If P is less than the middle square value, draw a down ↓ arrow

Condition 2: If P is greater than the middle square value, draw an up ↑ arrow


3)On the third line, write down M, followed by an either a 5↑ or a 4↓, based on the following conditions:


Condition 4: If the arrow on the second line is ↑, write down 5↑, then on its right side, write the notation /_ 750/

Condition 5: If the arrow on the second line is ↓, write down 4↓, then on its right side, write the notation /_ 250/


*At Right Column, 1st Row

.....P: 38’77

. 65 : 42’25 ↓

....M : 4↓ / 6250/


Step 3: Start computing the SE data.


Let’s begin with 6MN3


1) Looking for the ‘N’ digits


* At Left Column, 2nd Row


N3 : 09

(Blank)

....... 2 ... ← (take note, the 2 here is the second to the last digit of the given problem)


The letter N is included because we’re looking for that missing digit. Leave the second line blank and ask your self this question:

Q: What number needed to add to 0 to have a sum of 2?

A: 2


Write down on the second line “ Nx6 ” (6 is the double value of 3), followed by a colon :, then the answer “2”. On their right, decide which “pair of multiplicands” is the correct combination:


..... N3 : 09

... Nx6 : 2 . ..... 2, 7

............. 2


2) Looking for the M digits


Since we’re doing some parts mentally, directly write down the two combinations from the digits we gathered:


* At Left Column, 3rd Row


..... 23 : 4’09

... 2x6 : 1’2 .

............ 5’29

. Mx6 :(Blank)

............ 5 ← (this is the third to the last digit of the given problem)


Leaving some space in the second line blank, give you time to think first of what digit to write, by looking for a number needed to add to come up with the correct sum


..... 23 : 4’09

... 2x6 : 1’2 .

............ 5’29

. Mx6 : 0 . ... 0, 5

............ 5

6023


Underline the 0 since in P Chk, 4↓ indicates that the digits for M is 4 below.


Write down on the sixth line, the first complete digits of the first possible square root


Helpful Tip: Write down first 0, then 23 and then look for the first digit 6, so you would not be confused in writing down 6023


Do the Same procedures for the combination 73


* At Left Column, 4th Row

..... 73 : 49’09

... 7x6 : 4’2 .

............ 3’29

. Mx6 : 2 . ... 2, 7

............ 5

6273


On the right column, below the P- Chk, do the same procedures starting from Step 3, to complete the data for the second IPS ( 6MN7)


*At Right Column, 2nd Row


..... N7 : 49

... Nx4 : 8 . ..... 2, 7

............. 2


*At Right Column, 3rd Row


....... 27 : 4’49

... 2x14 : 2’8 .

.............. 7’29

... Mx4 : 8 . ... 2, 7

.............. 5

6227


*At Right Column, 4th Row


....... 77 : 49’49

..... 7x14 : 9’8 .

................ 9’29

..... Mx4 : 6 . ... 4, 9

................ 5

6477


Step 4: Arrange the 4 possible square roots from the lowest value to the highest by inserting the letters A, B, C, D on their right sides to avoid writing them again.


A - the lowest possible square root

B - 2nd to the lowest

C - 2nd to the highest

D – the highest of all


At Left Column ..... At Right Column


...... 6023 (A) .................... 6227 (B)

...... 6273 (C) ..................... 6477 (D)


Step 5: Use the Square Root locator to determine which of the 4 possible square roots will remain


42’25

(Blank)

36’00 .

78’25 / 2

39’12


Leave the second line (M) blank. Add 42’25 (H) and 36’00 (L).

We come up with a sum of 78’25. Divide by 2

Doing it mentally, always subtract the quotient by 6.


* At Left Column, 5th Row


42’25

39’06 \ ↓ (Using this middle value as reference, the P: 38’77 is lesser than)

36’00 /

78’25 / 2

39’12


The ↓ arrow indicates that the two higher values (C and D) are eliminated. A and B remained


Step 6: Use the 2nd Square Root Locator to determine which of the two remaining possible square roots, is the true square root of 38,775,529


39’06

(Blank)

36’00

75’06/2

37’53



Complete the data and determine where P is located


*At Right Column, 5ht Row


39’06\

37’53/ ↑

36’00

75’06/2

37’53


We therefore choose B as the true square root


√38,775,529 = 6,227

Thursday, August 12, 2010

Variation of SE Telegram

Given Problem:


√97,574,884


Left Column


√97’57’48’84

... 9 ............ 2

... 9 ............ 8


Right Column


.P : 97’57

95 : 90’25↑

M : 5↑ ... /9750/


Left Column, 2nd Row


. N2 : 04

Nx4 : 8 . ... 2, 7

......... 8


.. 22 : 04’04

.2x4 : 00’8

........... 4’84

.Mx4 : 4 . 1, 6

........... 8

9622 (A)


.. 72 : 49’04

.7x4 : 02’8

........... 1’84

.Mx4 : 7 . (odd product)

........... 8 ≠ √P



Right Column, 2nd Row


... N8 : 64

. Nx6 : 2 . .... 2, 7

........... 8



28: ≠ √P




... 78 : 49’64

7x16 : 11’2 .

............ 0’84

. Mx6 : 8 . .... 3, 8

............ 8

9878 (B)



Left Column, 5th Row


.. 100’ .. \

... 95’06/

... 90’25

. 190’25 / 2

... 95’12


Right Column, 5th Row


√97,574,884 = 9,878


In the above example, there are two possible square roots that ‘automatically eliminated’ due to the reason that the sub-products tend to end in odd digit, which violate the general rule of SSQ that all sub-products must be in even numbers.


Take note that there is always a pattern when a “not a square root of P” notation appears on the left column or right column.


If it is in left column3rd row, the next ≠ √P is on the right column, 2nd row or vice versa.

If it is in the left column 2nd row, the next ≠ √P is on the right column, 3rd row and vice versa.


The notations /_750/ at 5↑ and /_250/ at 4↓ (in P Chk), are only reminders that in arranging the possible square roots, make sure that there should be two values less than the indicated notation and two other possible square roots greater than it, or else, there could be an error in the process.



FINAL WORDS:


I believe that some people would agree with me that this kind of technique in taking the square root of numbers is much easier. But I don’t intend to replace the traditional method of taking the square root of numbers (long hand division).


I have good reasons why this method will benefit grade school children


1) It will sharpen their skills in adding and multiplying numbers.


2) There is little division and subtraction. I do believe that children hate to divide or subtract large numbers.


3) It will introduce them to the idea of what squares and square roots of numbers are, which they will learn soon in trigonometry (Pythagoreans Theorem), and higher mathematics.


4) The introduction of letters (M, N, P etc), might be strange to them but at that early age, SE prepares them in some basic ideas of algebra. It is up to the parents or teachers’ imaginations. It could be this way “imagine M as a box, where we don’t know what digit is inside that box. “


5) It gives them ideas of the relationships of numbers, such as, which numbers have the same last digits or what number should be multiplied by such number to get a product ending with this and that.


6) SE is Three-in-One (like a 3-1 coffee?). They will learn to know the basic squares of numbers and at the same time, sharpen their skills in addition and multiplication (repeated addition and multiplication of numbers), all in a one package.


7) It is more like a guessing game, a fun way of doing arithmetic. Knowing the missing digits challenges them to work it out than giving them a task of multiplying two numbers or adding four-digit numbers where they don’t have a clue, what the answers should look like.


I am advocating this method, to become part of the curriculum in elementary schools. I am looking for people who would agree with me with this idea and help me spread this message.


As a TOKEN OF APPRECIATION, I wish people will call this method, Square Edging MSM-1 (as part of my name is included in it).


Why MSM-1? The reason is that there are two other methods:


MSM- 2 Square Edging Numbers ending in 25, where MSM-1 failed


MSM-3 Universal Square Edging, a true way of taking the square root of any number, perfect square or not that is much easier to use than the long-hand division method.



Fidel Mendoza Jr. (Author of MSM-1)