Showing posts with label number. Show all posts
Showing posts with label number. Show all posts

Sunday, August 15, 2010

For Beginners

Kids,do you know that besides adding, subtracting, multiplying and dividing numbers, there are two other very interesting math operations that are also very useful in many activities? If you wish to know the area of a square or the measures of the sides of a right triangle, two special math operations - getting the square values or getting the square roots of numbers, are some of the more advanced math operations that you must learn.

They are advanced because unlike ordinary multiplication and division, their operations (methods of getting the answers), are much, much more tricky and difficult.

SQUARE
OF A
NUMBER

Getting the ‘square value’ of a number is like doing a special kind of multiplying a number, in which both the multiplicand and the multiplier are equally the same values. Sometimes, it is described as product of a number multiplied by itself.

Examples:

2 x 2 = 4

27 x 27 = 729
146 x 146 = 21,316

The value 4 is sometimes called the ‘square value’ of 2, or simply, “square of 2”. The same way, 729 is the “square of 27” and 21,316, the “square of 146”. Sometimes, instead of writing 2x2, 27x27 or 146x146, “a small number 2 in upper right side” of a given number is used as a symbol, telling you to multiply that number by itself. So, instead of 2x2, we write 22 = 4 and 27x27 as 272 = 729, while 146x146 as 1462 = 21,316.

Maybe, you are wondering why it is called ‘square’. Probably, early mathematicians noticed that the measure of the area of a square is always equal to a certain ‘number multiplied by itself’, so they named it, that way.

SQUARE ROOT

On the other hand, getting the square root of a number, need a very different way, of dividing a number. Unlike in ordinary division at which you need to mention the value of the divisor, in getting the square root of a number, both the divisor and the quotient are unknown and the difficult thing is, both divisor and the quotient must be equally in the same values.

Examples: 36 ÷ 3 = 12 36 ÷ 4 = 9 36 ÷ 6 = 6

In the above examples, 36 can be divided by 3 or 4 but the quotient would not be equal or the same with the divisor. Dividing 36 by 6, we can get a quotient equal to 6, which is the same exact value as to the divisor. In this situation, we can say that 6 is a square root of 36.

In doing this special kind of division, the symbol √ is used before a given number (example √144, read as, “the square root of one hundred forty-four’), to tell you to look for a divisor that will give a quotient, equal to that divisor. Dividing 144 by 12, we come up with a quotient equal to 12 (144 ÷ 12 = 12). Showing equal values for both divisor and quotient we can say then, that √144 = 12.

But there are occasions that the given numbers are in large values (example, √139,876). Getting the square root of such large valued numbers requires a very tedious and tricky method called ‘long hand division’. But as a practice, small valued numbers are introduced for grade school children, to make them easier to memorize.

Easy To Memorize “TABLE OF SQUARE ROOTS


√1 = 1

√4 = 2
√9 = 3
√16 = 4

√25 = 5

√36 = 6

√49 = 7

√81 = 9
√100 = 10


PERFECT SQUARES


Not all numbers from 1 to 100 give a square root in whole exact values. Most of them are in decimal values. Below is a list of examples of numbers, having no whole exact square root values:


√ 2, √3, √10, √99 , √28 , √50


Counting from 1 to 100, there are only ten numbers having square roots in ‘exact whole values’ and they are called perfect squares (or simply call them “PERKS”).


0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100


(Using a calculator, find the square roots of each numbers from 1 to 100 and write down which numbers have an exact whole numbers)


SET OF “PERFECT SQUARES” = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100}


The above numbers are called Perks because they are squares of whole numbers.


Easy To Memorize “TABLE OF SQUARES


1
2 = 1

22 = 4
3
2 = 9
4
2 = 16
5
2 = 25
62 = 36

7
2 = 49
8
2 = 64
9
2 = 81
102 = 100

Square Roots of 3-Digit/4-Digit Numbers

What is Square Edging?


The S.E. Method, in its original form, was intended as an alternative method beside the traditional long hand division method (search in NIST Square Root

http://www.itl.nist.gov/div897/sqg/dads/HTML/squareRoot.html

).

The only limitation of Square Edging is that it is only applicable in taking the square roots of numbers called perfect squares. The square roots of perfect squares are always in a “whole numbers”, never as fractions or decimal numbers. In fact, from 1 up to 100, there are only 10 perfect squares. While from 101 up to 10,000, there are only 90 perfect squares. The rest (9,900 other numbers) are useless in dealing with this format of S.E. But TRUST ME, it will WORTH A LOT.


I divided the topics into three;


1) 3D/4D.SE

2) 5D/6D.SE

3) 7D/8D.SE



Four Digit Square Edging (3D/4D.SE)


WARNING:

To easily understand this method of Square Edging, I highly recommend that you first study the SSQ Method.


Let us start by taking the square root of a four-digit number.


Given Problem: What is the square root of 2,304?


√2,304 = ?


Step 1

Count the digits of the given number. Re-group them by twos, starting from the last digit.


√23’04


Step 2

Find an index square, equal to or nearest to but less than the first group of digits of the given number. Write down the equivalent square root, below this first group of digits.


√23’04

4


Step 3:

Find a pair of index squares ending with the same last digit, as to the last digit of the given number. Write down below the last group of digits, their corresponding square roots.


04 is the last group of 23’04. The last digit of 04 is 4. There are two index squares that end with 4, these are 04 and 64. Their equivalent square roots are, 2 and 8.


√23’04

4 2

_ 8


It would be helpful, if you memorized the pairs of index squares having the same last digits. I provided one for you.


Table of Complementary Index Squares


12 = 01

92 = 81

1 + 9 = 10


22 = 04

82 = 64

2 + 8 = 10


32 = 09

72 = 49

3 + 7 = 10


42 = 16

62 = 36

4 + 6 = 10


02 = 00

52 = 25

NO PAIRS


Step 4

Copy the first digit of the upper square root to complete the lower square root.


√23’04

4 2 ← first possible square root

4 8 ← second possible square root


Now, you determined the two possible square roots, only one of them is the ‘true’ square root of 2,304


Final Step

One way to find out which of the two is the true square root, apply the 2D.SSQ


... 422 = 16’04 ← PSL

+4x2x2 = 1'6 ← SP1 (provided that 6 of 16 aligned to 0 of PSL)

............. 17’64 ← T-Sum (provided that T-Sum aligned to PSL)


....482 = 16’64 ← PSL

+4x8x2 = 6'4 ← SP1 (provided that 4 of 64 aligned to the second 6 of PSL)

............ 23’04 ← T-Sum (provided that T-Sum aligned to PSL)


Comparing the results, the second equation matches the given number. We are now sure that 48 is the correct answer.


√2,304 = 48


Helpful Tips:


There is another way of knowing which of the two square roots, is the true square root.


Tip 1: Check the first digit of any of the two possible square roots. Multiply it to a number next to it, higher by 1. Consider the product as our “square root indicator”.


The first digits of of both possible square roots of 42 and 48 are the same and that is 4

The number next to 4 is 5. 4 x 5 = 20

Sq. Rt. Indicator = 20


Tip 2: Compare the ‘square root indicator’ to the first group of digits of the given number


First Condition:

If the first group of digits is less than the square root indicator, pick the square root with lower value as your final answer


Second Condition:

If the first group of digits is greater than the square root indicator, pick the square root with higher value as your final answer.


The first group of digits of the given number is 23. It is greater than 20. So, pick 48 as the final answer.


√2,304 = 48


Three-Digit Square Edging (3D/4D.SE)


Now, let’s try a three digit number


Given Problem: What is the square root of 729?


√729 = ?


Step 1:

Re-group by twos


Important:

Take note, that if we re-group 729, it will appear as 7’29. But in the general rules of SSQ - in the process of squaring a number, the count of digits of a number must be doubled. So, a two-digit number must become four-digit number. To obey this rule, we should write 729 as 07’29.


√07’29


Step 2


√07’29

2


Step 3


√07’29

2 3

_ 7


Step 4


√07’29

2 3

2 7


Final Step

Next to 2 is 3.

2 x 3 = 6

Sq,Rt, Indicator = 6


07 > 6 (or 7 > 6)

27 > 23


√729 = 27


Author’s Note:


The truth is, this 3D/4D.SE in not really new. There are similar ideas that were posted in google and you.tube (this is one good example by Z-Math

http://www.ehow.com/how_2322332_square-root-number-mentally.html

).
I wish to give the credit to a certain Prof. Barbosa, for the Helpful tips (watch:

http://www.youtube.com/watch?v=WNJ2dCavUrA&feature=related

). I will admit, I got that from him.


But still, most of these ideas presented were limited only in taking the square roots of perfect squares in three or four digits. I will extend this method. I will show you how to take the square roots of perfect squares, even up to eight digits.

Friday, August 13, 2010

Square Roots of Big Numbers

Now, it’s time to deal with perfect square numbers in millions. It involved 7-digit or 8-digit numbers.


Given problem:


√ 22,877,089


Take note that this time, the number is in million (read as – twenty two million, eight hundred seventy seven thousand, eighty nine)

The instructions are the same except that there is an added letter – the letter M.


As an initial instruction, I request you to separate your paper into two columns – the left column and the right column


Step 1

Determine the two IPS (initial possible square roots). Write them on the left column


√ 22’87’70’89

4 M N 3

4 M N 7


Step 2

Create a Parameter Checker (P-Chk). Write them on the right column next to step 1


Helpful Tips:

1) Write first, Let P = 22’87..

2) Follow it up by writing the middle numbers (45..2 = 20’25..). Leave two spaces above and below.

3) Check the middle square value (20’25..)

First Condition: If P is less than the middle square value, write down below it the lower numbers ( 40..2 = 16’00..). Enclose them and write 4↓ on the left side. Write the letter P on the right side.

Second Condition: If P is greater than the middle square value, write down above it the higher numbers ( 50..2 = 25’00..). Enclose them and write 4↓ on the left side. Write the letter P on the right side.

Third Condition: If you choose 4 , simply write down M = 4, 3, 2, 1, 0

Fourth Condition: If you choose 4 , simply write down M = 4, 3, 2, 1, 0

Optional: You could ignore writing the whole data (see example in 5D/6D.SE). Leave a blank or write it as “ . . . = . . .


P Chk

...... Let P = 22’87…

..... / 50..2 = 25’00.. \

..5↑\ 45..2 = 20’25.. / P

.......... . . . = . . .

M = 5, 6, 7, 8, 9


Step 3:

Find out the missing digits


Left Column, Second Row

4MN32 = ..09

. Nx3x2 = ..8 .

………… ..89

Nx6 = ..8 …. N = 3, 8

4M33

4M83


Right Column, Second Row


4MN72 = ..49

..Nx7x2 = ..4 .

………… ..89

Nx4 = ..4 …. N = 1, 6

4M17

4M67


Left Column, 3rd Row


4M332 = ..09’09

... 3x3x2 = ..1’8 .

..……..…..10’89

..Mx3x2 = ..0

................. ..0’89

Mx6 = ..0 …. M = 0, 5

4533


Right column, 3rd row


4M172 = ..01’49

... 1x7x2 = ..1’4 .

............... ..02’89

..Mx7x2 = ..8

................. ..0’89

Mx4= ..8 …. M = 2, 7

4717


Left Column, 4th row


4M832 = ..64’09

... 8x3x2 = ..4’8 .

............... ..68’89

..Mx3x2 = ..2

................. ..0’89

Mx6 = ..2 …. M = 2, 7

4783


Right Column, 4th row


4M672 = ..36’49

... 6x7x2 = ..8’4 .

............... ..44’89

..Mx7x2 = ..6

................. ..0’89

Mx4= ..6 …. M = 4, 9

4967


Left Column, 5th row


Sq. Rt. Loc 1

↓4533 47174783 4967↑

....../ H = 25’00.. \

.. ↑ \M = 22’56.. / P

….... L = 20’25..


Right Column, 5th row

Sq. Rt. Loc 2


↓4783 …. 4967↑

....... H = 25’00..

. ↓ / M = 23’78..\ P

.......\ L = 22’56.. /


Left Column, last row


√ 22,877,089 = 4,783


Question: How I got the Middle Numbers of the Sq. Rt. Loc 1?


H = 25’00..

M = ?

…. L = 20’25..

……… 45’25 / 2

……… 22’62 – 6 = 22’56


1) Add H and L

2) Divide by 2 (I use this “___/2” to represent division by 2)

3) Subtract the quotient by 6. Why? Doing it makes the middle square value much nearer to its ‘true’ square value.


Important

You do this only on the first square root locator.

On Sq, Rt. Loc. 2, do the same procedures except the last one.


Note from the Author:

The use of up and down arrows and the letters H, M and L will simplify the equations. Also, omitting the "nn" and "mm" notations save your time and effort in writing unnecessary things. But for beginners, I strictly request to follow the procedures on the topic – “Five/Six-Digit Equare Edging”